# Line slope calculator 10x+3y=90

**Straight line given by points A[6; 10] and B[9; 0]**

## Calculation:

**Slope-intercept form of line:**y = -3.3333x+30

**Canonical form of the line equation:**10x+3y-90 = 0

**Parametric form of the line equation:**

x = 3t+6

y = -10t+10 ; t ∈ R

**Slope:**m = -3.3333

**Slope angle of line: φ =**-73°18'3″ = -1.2793 rad

**X intercept:**x

_{0}= 9

**Y intercept:**y

_{0}= q = 30

**Distance line from the origin:**d

_{0}= 8.6204

**The length of the segment AB: |AB| =**10.4403

**Vector: AB =**(3; -10)

**Normal vector: n =**(10; 3)

**Midpoint of the segment AB: M =**[7.5; 5]

**Perpendicular Bisector equation:**3x-10y+27.5 = 0

**Vector OA = (6; 10) ; |OA| = 11.6619**

**Vector OB = (9; 0) ; |OB| = 9**

**Scalar product OA .OB = 54**

**Angle ∠ AOB = 59°2'10″ = 1.0304 rad**